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Quantity I: Age of father, if age of Abhishek is 1/6th of his father’s and 10 years after Abhinav’s age becomes half of Abhishek’s father’s age.
Quantity II: Age of father, if 5 years ago age of A’s father was three times the age of A and 5 years hence his age will be double A’s age.
Quantity I > Quantity II
Quantity I ≥ Quantity II
Quantity II > Quantity I
Quantity II ≥ Quantity I
Quantity I = Quantity II or Relation cannot be established
I: ………………………Abhishek……………Father ………………………..…..1…………………….6 (1) 10 years after. Abhinav Father . 1 ……………………2 (2) Now Abhivav is 10 years old so after 10 years he will be 20 Put in (1) father = 40 Now 40-10 = 30 II: . A A’s father 5 years ago 1 3 5 years hence 1 2 So 3-2 = 1 1 == 10 3 == 30 So 30+5 = 35 II>I
Hence, option 3 is the correct answer.
By: Amit Kumar ProfileResourcesReport error
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