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Quantity I: A shopkeeper marks up an item by 50% above the cost price and sold it after offering a discount of 20%. The profit earned by shopkeeper is what % less than the profit earned by him, if he marks up the item by 75% above the cost price and offers a discount of 20%.
Quantity II: The area of the square built on the side of a square is what percentage less than the area of a square build on the diagonal of a square?
I < II
From I: Let CP be Rs. x. MP = Rs.1.5x SP = 1.5x*0.8 = Rs.1.2x Profit = 1.2x – x = Rs.0.2x Also, CP be Rs.x. MP = Rs.1.75x SP = 1.75x*0.8 = Rs.1.4x Profit = 0.4x Required% = (0.4x – 0.2x)/0.4x*100 = 50% From II: Let ‘x’ be the side of the square. Length of the diagonal of square = (2)^1/2a units Area of square = a^2 units Area of square built on side of square = [(2)^1/2a]^1/2 = 2a^2 units Required% = (2a^2 – a^2)/2a^2 * 100 = 50% I = II
Hence, option 4 is the correct answer.
By: Amit Kumar ProfileResourcesReport error
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