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Directions : The given tables show the time taken by filling and emptying pipes to fill and empty a tank respectively. Some data is missing. Study the table carefully and answer the questions based on data in table and particular questions.
11/40th of a tank was filled. Pipes C and D were opened. After some time pipe P was also opened. Pipe P was closed after time equal to the time it was opened at the starting . If after closing pipe P, the tank was filled in 6 minutes, find what fraction of tank was filled by pipe C?
7/8th
3/8th
2/7th
5/7th
None of these
C+D = 1/48 + 1/40 = 11/240 Let after x minutes P was opened,
so P was opened for x minutes [as given] So 11/40 + (1/48 + 1/40) * x + (1/48 + 1/40 – 1/60)*x + (1/48 + 1/40) * 6 = 1 OR 11/40 + (1/48 + 1/40) * 2x – 1/60 * x + (1/48 + 1/40) * 6 = 1 Solve, x = 6 minutes So C was opened for 2x+6 = 18 minutes So filled 1/48 * 18 = 3/8 of tank
Hence, option 2 is the correct answer.
By: Amit Kumar ProfileResourcesReport error
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