Two pipes A and B are opened simultaneously and it is found that due to the leakage in the bottom 17...........

Quantitative Aptitude ( CCS) Bar Graph

Time taken by the pipes to fill a tank/cistern (hours/minutes)

Two pipes, A and B are opened simultaneously and it is found that due to the leakage in the bottom, 17/7 minutes are taken extra to fill the tank. If the tank is full, in what approximate time would the leak empty it?

27 minutes

32 minutes

36 minutes

39 minutes

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Explanation:

Explanation :
Total time taken by both pipes before the leak was developed = 60/7 minutes
now, leaks is developed which will take T time to empty the tank so, (1/15 +1/20 – 1/T) = 1/11
solve for T, we will get 660/17 minutes = 39 minutes (approx.)