A tank is to be filled by using pipes B and D simultaneously After 9 minutes some garbage was observ...........

Quantitative Aptitude ( CCS) Data Table

Direction : Study the following table to answer the questions that follow. Some values are missing. Study the table carefully and answer the questions based on data in table and particular questions.

Pipes	Time taken to fill the tank (in min.)	Pipes	Time Taken to empty the tank (in min.)
A	15	P	20
B		Q	16
C	25	R
D	30	S

A tank is to be filled by using pipes B and D simultaneously. After 9 minutes, some garbage was observed in tank so pipes B and D were closed and pipe S was opened. After 6 minutes, it was found, that tank is clean so pipe S was closed and again pipes B and D were opened, after which they filled the tank in 6 minutes. If pipe S alone can empty 2/9th tank in 4 minutes, in how much time pipe B can fill the fill tank?

20 minutes

16 minutes

15 minutes

24 minutes

18 minutes

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Explanation:

S can empty 2/9th tank in 4 minutes, so full tank in 9/2 * 4 = 18 minutes
So now
(1/B + 1/30) * 9 + (-1/18) *6 + (1/B + 1/30) * 6 = 1
(1/B + 1/30) * 15 = 1 + 1/3
(1/B + 1/30) * 15 = 4/3
Solve, B = 18

Hence, option 5 is the correct answer.