B and C can complete the whole project 4 in 6 days working together A is 20 more efficient than C an...........

Quantitative Aptitude ( CCS) Data Table

Directions : The following table shows the number of days for which 4 individuals A, B, C and D worked on 5 different projects numbered 1 to 5. It also shows the part of respective project that could not be completed by individuals in time. Some values are missing which are denoted by symbol (-). With the help of information in questions and table below answer the questions that follow.

Project No.	No. Of days for which individuals worked on different projects				Part of project uncompleted after all worked
Project No.	A	B	C	D	Part of project uncompleted after all worked
1	6	6	2	3	1/3
2		3	4
3
4	5	3	2		1/6
5	2	2	3	5	1/12

B and C can complete the whole project 4 in 6 days working together. A is 20% more efficient than C and 40% less efficient that B. How many days did D work on project 4 if D can complete whole project 4 in 18 days?

5 days

4 days

2 days

1 day

6 days

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Explanation:

Efficiency — A : C = 120 : 100 = 6 : 5
So days ratio = 5 : 6
Similarly, A : B = 60 : 100 = 3 : 5, so days 5 : 3
B/A = 3/5, A/C = 5/6
So ratio of days for B : A : C is 3 : 5 : 6 …………(1)
Now — B and C can complete the whole project 4 in 6 days working together,

and ratio of no. of days in which they can complete work alone is B and C from (1) is 3 : 6 = 1 : 2
So
1/x + 1/2x = 1/6
Solve, x = 9
So B can complete work in 8 days, C in 18 days and then A in 15 days
Now, let D worked for ‘y’ days on project 4. So
1/15 *5 + 1/9 * 3 + 1/18 * 2 + 1/18 * y = 1 – 1/6
Solve, y = 1 day

Hence, option 4 is the correct answer.