Project 3 was to be completed in 6 days To complete project in time all A B C and D decided to work ...........

Quantitative Aptitude ( CCS) Data Table

Directions : The following table shows the number of days for which 4 individuals A, B, C and D worked on 5 different projects numbered 1 to 5. It also shows the part of respective project that could not be completed by individuals in time. Some values are missing which are denoted by symbol (-). With the help of information in questions and table below answer the questions that follow.

Project No.	No. Of days for which individuals worked on different projects				Part of project uncompleted after all worked
Project No.	A	B	C	D	Part of project uncompleted after all worked
1	6	6	2	3	1/3
2		3	4
3
4	5	3	2		1/6
5	2	2	3	5	1/12

Project 3 was to be completed in 6 days. To complete project in time, all A, B, C and D decided to work in pairs in alternate days. A and C on 1^st day, B and D on 2^nd day, A and C on 3^rd, and so on. But they could not complete project in time. What percent of project 3 remain uncompleted if A, B, C and D can complete whole project 3 in 12, 18, 20 and 15 days respectively?

27 3/4%

21 2/5%

25 1/4%

24 2/3%

23 1/3%

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Explanation:

Project is to be completed in 6 days.

They all worked in pairs on alternate means all worked for 3 days each.
So
On 1^st day, work completed by A and C = 1/12 + 1/20 = 2/15
On 2^nd day, work completed by B and D = 1/18 + 1/25 = 11/90
1^st pair worked for 3 days, so work completed by them = 2/15 * 3 = 2/5
Similarly, by B and D = 11/90 * 3 = 11/30
So part of project uncompleted= 1 – (2/5 + 11/30) = 7/30
So % = 7/30 * 100 = 70/3%