A and B can do a job in 25 days They started working together and after 10 days B left the work Then...........

Quantitative Aptitude ( CCS) Time and work

A and B can do a job in 25 days. They started working together and after 10 days B left the work. Then A did the remaining work in 60 days. Then find in how many days B alone can do the same work?

30 days

33 (1/3) days

40 days

45 days

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Explanation:

Solution:
Let total work =25
1 day work of A and B =1
Remaining work after 10 days= 25-10=15
B do 15 work in 60 days
means 25 work in 60*25/15=100 days
A+B = 25 ———4 (Total Work= 10)
B =100————1
A=—————- 4-1=3
B=100/3