A B and C can do a work in 18 30 and 45 days respectively If they start work with A works the first ...........

Quantitative Aptitude ( CCS) Time and work

A, B, and C can do a work in 18, 30, and 45 days respectively. If they start work with A works the first day, C the second day and B the third and fourth day. If this process continues than find in how many days they will complete the work?

26 2/3 days

28 days

27 2/3 days

27 days

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Explanation:

Solution:
A = 18, B = 30, C = 45
LCM = 90
A = 90/18 = 5, B = 3, C = 2
1st day…………2nd day……………3rd day
A=5……………..C=2………………….B=3+3
than
4 days work = 5 + 2 + 6 = 13
Make it near total (90)
4*6…………….. 13*6
24………………..78
A -> 1 ……………..5
B -> 1……………….2
C -> 1……………….3
Add
24+1+1+1=27 days……………..(78+5+2+3) = 88 days
Now 90-88 = 2 work pending
B does 3 work in 1 day, so 2 in 2/3. So total 27 2/3 days