What is the difference in time taken by Car A to cover 80 Km when it moves at a constant speed and t...........

Quantitative Aptitude ( CCS) Data Table

Direction : Study the following information and answer the questions that follow:

There are three cars A, B and C with different maximum speed. The minimum speed of these cars is 0 kmph and the maximum speed is marked in the speedometer of these cars. Rest of the speeds are marked at equal intervals in the speedometer. The table below shows the maximum speed of the car and the number of points marked in the speedometer of the car. The first point in the speedometer represents Speed of 0 kmph and the last point represents the maximum speed.
(Example: If the maximum soeed of the car is 100 kmph and there are 11 points marked in the speedometer then each point represents an increase of 10kmph with 1^st point as 0 kmph).

Car	Maximum Speed (in Kmph)	Number of points marked in Speedometer
Car A	150	16
Car B	180	37
Car C	120	13

What is the difference in time taken by Car A to cover 80 Km when it moves at a constant speed and the pointer of the speedometer throughout the journey points at the 5^th position (5^th point) and the time taken by Car C to cover 100 km when moving at a constant speed with the pointer of the speedometer pointing at point 7?

20 minutes

40 minutes

50 minutes

30 minutes

1 hour

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Explanation:

Since the point 1 is for speed 0;

so remove 1 from each of the point of speedometer to find the speed / division:
For Car A each division represents= 150/ (16-1)= 10 kmph
For Car B each division represents= 180/ (37-1)= 5 kmph
For Car C each division represents= 120/ (13-1)= 10 kmph

For Car A when pointer is at 5^th position it means car is moving at (5-1)*10= 40 kmph
For Car C when pointer is at 7^th position means the car is moving at (7-1)*10= 60 kmph
Time difference= 80/40 *60 -100/60*60 =120-100=20 minutes

Hence, option 1 is the correct answer.