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Directions : There are 3 bags containing 3 colored balls – Black, Green and White. Bag 1 contains: 15 black balls. Probability of drawing a white ball is 2/5. The ratio of number of green ball to the number of white ball is 3:4.
Bag 2 contains: Number of black balls and number of white balls are equal. Number of green ball is 4/5th of the number of green ball in bag 1. The probability of black ball is 5/14.
Bag 3 contains: Number of Black Balls is (1/3)rd of the total number of black balls in Bag 1 and Bag 2 together. Number of Green ball is half of the number of white ball in bag 1. The probability of drawing a white ball is 3/7
If one ball is drawn from bag 1 and 1 ball is drawn from bag 3. Find the probability the these are green ball.
3/35
9/245
11/245
4/35
8/35
Bag 1= 15 Black, Green = 3x, white = 4x P(white)= 4x/(15+4x+3x)=2/5 => x= 5 B= 15; G= 15; W= 20 Bag 2: Black= White=x Green=4/5*15=12 P(black)=x/(12+2x)= 5/14 x=15 B=15; G=12; W=15 Bag 3: B= 1/3* (15+15)= 10 G= ½*2=10 White=x P(white)= x/ (10+10+x)=3/7 x=15 P(Green)= 15/50 * 10/35 = 3/35
Hence, option 1 is the correct answer.
By: Amit Kumar ProfileResourcesReport error
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