X Y and Z starts the race from position A What distance more would boat Z have travelled than boat Y...........

Quantitative Aptitude ( CCS) Case Studies

Direction : Study the following information and answer the questions that follow:

In a boating competition there are 3 boats X, Y and Z taking in the race. The river in which the race is to be held is divided into three equal parts AB, BC and CD. To complete the race a boast must travel from A to D downstream and back from D to A upstream.
The speed of stream in part BC is 50% of the speed of stream in part AB, while the speed of stream in part CD is 150% of the speed of the stream in part AB.
Speed of boat X in still water= 6 kmph;
Speed of boat Y in still water= 5 kmph
Speed of boat Z in still water= 8 kmph

X, Y and Z starts the race from position A. What distance more would boat Z have travelled than boat Y at the time when boat Y reaches point B? (Distance AD= 210 km and speed is stream in region BC is 1 kmph)

20 km

25 km

27 km

28 km

30 km

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Explanation:

Time taken by boat Y to reach B= (Distance AB)/ downstream speed for Y= 70/(5+2)=10 hours
Time taken by Z to travelled AB= 70/ (8+2)=7 hours
In this extra 10-7 hours=3 hours;

Z is in region BC where speed of stream is 1 kmph
So distance travelled by Z in region BC in 3 hours= 3* (8+1)= 27 km
So Z is 27 km ahead of Y when Y reaches B

Hence, option 3 is the correct answer.