A and B can do a piece of work in 25 days B and C can do the same piece of work in 30 days C and A c...........

Quantitative Aptitude ( CCS) Time and work

A and B can do a piece of work in 25 days. B and C can do the same piece of work in 30 days. C and A can do the same work in 37.5 days. In how many days will A alone do the same work?

100 days

60 days

50 days

75 days

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Explanation:

Solution :
A+B =25 ————6 (1 days work) [total=150]
B+C =30————-5 (1 days work)
C+A =37.5———–4(1 days work)
Total = LCM of 25,30,37.5
1 day work=total work/days
adding the three equation
2(A+B+C) = 15
A+B+C 1 day work = 7.5
A+B+C – (B+C) =7.5 – 5 = 2.5
A =150/2.5 = 60 days