A and B can complete a work in 12 and 20 days respectively After 4 days they are joined by C who can...........

Quantitative Aptitude ( CCS) Time and work

A and B can complete a work in 12 and 20 days respectively. After 4 days, they are joined by C who can complete the same work in 24 days, how much work will remain uncompleted after 2 more days?

53/60

41/60

13/60

7/60

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Explanation:

Explanation:
They work for 4 days. So complete
(1/12 + 1/20) × 4 = 8/15 of work
Now: In next 2 days all A, B, C completed
(1/12 + 1/20 + 1/24) × 2 = 7/20 of work
So total work completed = 8/15 + 7/20 = 53/60
So remaining work = 1 – 53/60 = 7/60