2 groups A and B contain some people each Efficiencies of all people in group A is same while t...........

Quantitative Aptitude ( CCS) Time and work

2 groups A and B contain some people each. Efficiencies of all people in group A is same while that in group B is same. 3 workers from group A and 6 from group B can complete the work in 20 days. 8 workers from group A and 4 from group B can complete the work in 10 days. Find the number of days in which 1 person from each group can complete the work working together.

96 days

72 days

90 days

54 days

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Explanation:

Explanation:
The question is same as 3 m and 6 w complete work in 20 days. And 8 m and 4 w complete work in 10 days.
So 3A + 6B = 20 => 60 A + 120B = 1
And 8A + 4B = 10 => 80 A + 40B = 1
So 60 A + 120B = 80 A + 40B
80B = 20A
B = A/4
So – 8A + 4 * A/4 = 10
or 9A = 10
So 9 workers of group A can complete work in 10 days
Required to find A + B = A + A/4 = 5A/4
So
9 * 10 = 5/4 * x
Solve, x = 72 days