What is the area of a triangle having perimeter 32 cm one side 11 cm and difference of other two sid...........

Quantitative Aptitude ( CCS) Mensuration 2D

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What is the area of a triangle having perimeter 32 cm , one side 11 cm and difference of other two sides 5 cm ?

8√30 sq cm

5√35 sq cm

6√30 sq cm

8√2 sq cm

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Explanation:

Let the sides of triangle be a,b and c respectively
2s=a+b+c=32
11+b+c=32
b+c=21……(i)
b-c=5 ……..(ii)
from equation i & ii , we get
2b=26 Hence b=13,c=8
2s=32 , Hence s=16
a=11,b=13,c=8
Area of triangle = √{s(s-a) (s-b) (s-c)}
=√{16 (16-11) (16-13) (16-8)}
=8√30 sq cm