N is the greatest number which divides 1305 4665 and 6905 and gives the same remainder in each case ...........

Quantitative Aptitude ( CCS) LCM, HCF

N is the greatest number which divides 1305, 4665 and 6905 and gives the same remainder in each case. What is the sum of the digits in N?

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Explanation:

If the remainder is same in each case and remainder is not given,

HCF of the differences of the numbers is the required greatest number
6905 – 1305 = 5600
6905 – 4665 = 2240
4665 – 1305 = 3360
Hence, the greatest number which divides 1305, 4665 and 6905 and gives the same remainder, N
= HCF of 5600, 2240, 3360
= 1120
Sum of digits in N
= Sum of digits in 1120
= 1 + 1 + 2 + 0 = 4

Hence, option 1 is the correct answer.