Find the greatest number of five digits which when divided by 3 5 8 12 leaves 2 as remainder ........

Quantitative Aptitude ( CCS) LCM, HCF

Find the greatest number of five digits which when divided by 3, 5, 8, 12 leaves 2 as remainder

99999

99948

99962

99722

LCM (3, 5, 8, 12) ⇒ 3 × 5 × 8 = 120

⇒Now greatest five digit number is 99999

On dividing 99999 by = 120 (LCM) we get remainder –

= 99999/120, remainder = 39

⇒By subtracting remainder from 99999 we get the greatest five digit number which is completely divisible by given numbers (3, 5, 8, 12).

∴ 99999 – 39 = 99960

⇒Now, we required the greatest five digit number which when divided by (3, 5, 8, 12) leaves remainder 2 in each case.

⇒ add 2 in the 99960

= 99960 + 2 = 99962

Hence, option 3 is the correct answer.

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