Lakha and Tipu are in team A and Mukhia and Khachra are in team B if Both the team decided to comple...........

Quantitative Aptitude ( CCS) Data Table

Direction : Study the following Table and answer the questions that follow:

Persons	No. of days they worked	Percentage of work done to complete the project
Bhuvan	6	15%
Lakha	8	25%
Bhura	5	20%
Kachara	3	15%
Tipu	4	25%

Lakha and Tipu are in team A and Mukhia and Khachra are in team B. if Both the team decided to complete the same amount of work separately then find out which team is more efficient and by how much days ?

Team A by 2/3 days

Team B by 6/5 days

Team A by 6/5 days

Team B by 2/3 days

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Explanation:

We can find the total work by taking LCM of each team member
LCM ( 32 , 16, 20, 20)
= 160 unit
Now we can find efficiency of each person
Team A
Lakha = 5 unit
Tipu = 10 unit
1 day work of Lakha and Tipu = 15 unit
Days required to complete the work by Team A = 160/15
Team B
Mukhia = 8 unit
Kachara = 8 unit
1 day work of Lakha and Tipu = 16 unit
Days required to complete the work by Team A = 160/16
from the efficiency it is clear that Team B is more efficient but by how much days
= (160/15) – (160/16)
= 2/3 days

Hence, option 4 is the correct answer.