Quadratic Equations

Quantitative Aptitude ( CCS)

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I. 2x²–6x–48 = 0

II. y^2–13y+42 = 0

x>y

x<y

x≤y

x≥y

Explanation:

2x²–4x–48 = 0
2(x²–2x–24) = 0
x²–2x–24 = 0
x²–6x+4x–24 = 0
x = +6, –4
y²–13y+42 = 0
y²–7y–6y+42 = 0
y = +7, +6
Hence, x≤y

By: MIRZA SADDAM HUSSAIN

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