The sides of a triangle are 6 cm 11 cm and 15 cm The radius of its in circle is ........

Quantitative Aptitude ( CCS) Mensuration 2D

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The sides of a triangle are 6 cm, 11 cm and 15 cm. The radius of its in-circle is:

3*(2)^0.5

(4/5)*(2)^0.5

(5/4)*(2)^0.5

6*(2)^0.5

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Explanation:

Explanation: Let a, b, c be the sides of the triangle. Then, we know
Semi-perimeter = 1/2 * (a + b + c) = 1/2 * (6 + 11 + 15) = 16 cm.
Area = [s*(s-a)*(s-b)*(s-c)]^0.5 = [16*10*5*1]^0.5 = 20(2)^0.5 cm^2.
Therefore, Radius of in-circle = Area/Semi-perimeter = 20(2)^0.5/ 16 = (5/4)*(2)^0.5 cm.