send mail to support@abhimanu.com mentioning your email id and mobileno registered with us! if details not recieved
Resend Opt after 60 Sec.
By Loging in you agree to Terms of Services and Privacy Policy
Claim your free MCQ
Please specify
Sorry for the inconvenience but we’re performing some maintenance at the moment. Website can be slow during this phase..
Please verify your mobile number
Login not allowed, Please logout from existing browser
Please update your name
Subscribe to Notifications
Stay updated with the latest Current affairs and other important updates regarding video Lectures, Test Schedules, live sessions etc..
Your Free user account at abhipedia has been created.
Remember, success is a journey, not a destination. Stay motivated and keep moving forward!
Refer & Earn
Enquire Now
My Abhipedia Earning
Kindly Login to view your earning
Support
Type your modal answer and submitt for approval
A vessel in the shape of a cuboids’ contains some water. If 3 identical spheres are immersed in the water, the level of water is increased by 2 cm. If the area of the base of the cuboids is 160 cm2 and its height is 12 cm. determine the radius of any of the spheres?
2.36 cm
2.94 cm
2.25 cm
2.67 cm
Given, The area of the cuboids’= 160 cm2 Level of water in the vessel increased = 2 cm Volume of the vessel = 160 *2 cm2 =320 cm2 ……………………………….. (i) Volume of each sphere = (4/3)∏×(r)3 Total volume of 3 spheres = 3×(4/3)∏×(r)3……………..(ii) Now equating equation (i) and (ii) we get 320 = 3×(4/3)∏×(r)3 R= 2.94 cm. The radius of the sphere so obtained is 2.94 cm.
By: MIRZA SADDAM HUSSAIN ProfileResourcesReport error
Access to prime resources
New Courses