send mail to support@abhimanu.com mentioning your email id and mobileno registered with us! if details not recieved
Resend Opt after 60 Sec.
By Loging in you agree to Terms of Services and Privacy Policy
Claim your free MCQ
Please specify
Sorry for the inconvenience but we’re performing some maintenance at the moment. Website can be slow during this phase..
Please verify your mobile number
Login not allowed, Please logout from existing browser
Please update your name
Subscribe to Notifications
Stay updated with the latest Current affairs and other important updates regarding video Lectures, Test Schedules, live sessions etc..
Your Free user account at abhipedia has been created.
Remember, success is a journey, not a destination. Stay motivated and keep moving forward!
Refer & Earn
Enquire Now
My Abhipedia Earning
Kindly Login to view your earning
Support
Type your modal answer and submitt for approval
The surface area of the solid metallic sphere is 616 cm³. It is melted and recast into a cone of height 28 cm. find the diameter of the base of the cone so formed?
10 cm
11 cm
12 cm
none of these
The height of the cone = 28 cm Surface area of the sphere= 616 cm³ We know that the surface area of the sphere = 4∏r2 =4∏r2 = 616 = r2= 49 = r =7 Radius of the sphere = 7 cm Let R be the radius of the cone Volume of the cone = (1/3)∏r2h = (1/3)∏r228………………….(i) Volume of the sphere= (4/3)∏r3 = (4/3)∏73 …………………..(ii) Comparing equation (i) and (ii) R2= 49 R=7 Diameter of the cone = 7*2 = 14 cm The diameter of the base of the cone is 14 cm
By: MIRZA SADDAM HUSSAIN ProfileResourcesReport error
Access to prime resources
New Courses