send mail to support@abhimanu.com mentioning your email id and mobileno registered with us! if details not recieved
Resend Opt after 60 Sec.
By Loging in you agree to Terms of Services and Privacy Policy
Claim your free MCQ
Please specify
Sorry for the inconvenience but we’re performing some maintenance at the moment. Website can be slow during this phase..
Please verify your mobile number
Login not allowed, Please logout from existing browser
Please update your name
Subscribe to Notifications
Stay updated with the latest Current affairs and other important updates regarding video Lectures, Test Schedules, live sessions etc..
Your Free user account at abhipedia has been created.
Remember, success is a journey, not a destination. Stay motivated and keep moving forward!
Refer & Earn
Enquire Now
My Abhipedia Earning
Kindly Login to view your earning
Support
Type your modal answer and submitt for approval
The diameters of the internal and external surface area of hollow spherical shell are 10cm and 6 cm respectively. If it is melted and recast into a solid cylinder of length of 223 , find the diameter of the cylinder?
14 cm
18 cm
12 cm
8 cm
Given, Internal diameter of the hollow sphere = 6 cm Internal radius of the hollow sphere = 6/2 cm = 3 cm External diameter of the hollow sphere = 10 cm External radius of the hollow sphere = 10/2 cm = 5 cm Volume of the hollow spherical shell = (4/3)∏×R3−r3 = (4/3)∏×53−33 …………………… (i) Given the length of the solid cylinder =83 cm Let the radius of the solid cylinder be h cm Volume of the cylinder = ∏×r2×h = ∏×r2×8/3 …………….. (ii) Now equating both the above marked equations in order to obtain the radius of the cylinder r2 = 49 r =7 d= 7 * 2 =14 cm
By: MIRZA SADDAM HUSSAIN ProfileResourcesReport error
Access to prime resources
New Courses