Explanation:

2.2 dm³ of brass is to be drawn into a cylindrical wire of 0.25cm diameter
Radius of the wire (r) = d/2
=0.25/2 = 0.125*10^-2cm
Now, 1cm =0.01m
So, 0.1cm=0.001m
Let the length of the wire be (h)
Volume of the cylinder= ∏r²h
Volume of brass of 2.2 dm³ is equal to volume of cylindrical wire.
22/7(0.125×10−2)²×h=2.2×10−3
H=448 m
The length of the cylindrical wire is 448m