Explanation:

Given that a metallic block which is rectangular of dimension 11dm*1m*5dm
Given that the diameter of each bullet is 5 cm
Volume of the sphere = (4/3)∏r³
Dimensions of the rectangular block = 11dm*1m*5dm
Since we know that 1 dm = 10^-1m
11*10^-1*1*5*10^-1 = 55*10^-2 ……………………….(i)
Diameter of the bullet = 5cm
Radius of the bullet = 5/2 = 2.5 cm
So the volume of the rectangular block equals to the sum of the volumes of the n spherical bullets
Let the number of bullets be n
55*10^-2= n((4/3)∏1³)
= n= 8400
Numbers of bullets formed were 8400.