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Train A travelling at 126 km/hour speed, completely crosses Train B in 9 seconds. Train B is half the length of Train A and is travelling at a speed of 90 km/hour in the opposite direction (towards Train A). How much will Train A take to cross a platform of length 690 metres?
28 seconds
32 seconds
25 seconds
30 seconds
Let the length of train A be x meter. ∴ Length of train B = x/2 meter Speed of train A = 126 kmph = (126 × 5/18) m/sec = 35 m/sec. Speed of train B = 90 kmph = (90 × 5/18) m/sec. = 25 m/sec. = length of trains A and B/ Time taken in crossing = 35 + 25 = [x(x/2)/9] = 60 × 9 = 3x/2 = 3x = 90 × 12 = x = (90 × 120/3) = 360 meter ∴ Time taken in crossing the platform = Length of train A and Platform/(Speed of train A) = (360 + 690)/35 = 1050/35 seconds = 30 seconds
By: Pranav Gupta ProfileResourcesReport error
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