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A plane left 30 minutes later than the scheduled time and in order to reach the destination 1500 km away in time, it had to increase the speed by 250 km/hr from the usual speed. Its usual speed is:
720 km/hr
730 km/hr
740 km/hr
750 km/hr
Usual speed of plane = x kmph ∴ New speed = (x + 250) kmph ∴ 1500/x – 1500/(x + 250) = 30/60 = 1500 (x + 250 - x)/ [x(x + 250)] = 1/2 = x (x + 250) = 750 (750 + 250) = x= 750 kmph
By: Pranav Gupta ProfileResourcesReport error
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