Sunil left for city lsquo x rsquo from city 39 y 39 at 5 50a m He travelled at the speed of 80 km hr...........

Quantitative Aptitude ( CCS) Time & distance

Sunil left for city ‘x’ from city 'y' at 5.50a.m. He travelled at the speed of 80 km/hr. for 2 hours15minutes. After that the speed was reduced to 60 km/hour. If the distance between two cities is 350 kms at what time did Sunil reach the city ‘Y’?

10.05 a.m.

10.35 a.m.

9.50 a.m

11.55 a.m

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Explanation:

Distance between two cities = 350 km
Distance travelled by Sunil with the speed of 80 km/ hr in 9/2 hours or 2.25 hr.
= 80 × 2.25 km = 180 km
∴ Remaining distance = 350 – 180 = 170 km
Speed = 60 km/hr
Time taken to reach in city
x = 170/60 = 2.83 hr
Total time = 2.5 + 2.85
= 5.08 hr = 305 minutes
= 6 hours 5 minute
Sunil started journey at 5.50 a.m. & finished the journey at = 11.55 a.m.