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On walking at 3/4 of his usual speed a man reaches his office 20 minutes late. What is the usual time taken by him in reaching his office?
75 minutes
60 minutes
40 minutes
30 minutes
Actual speed = x kmph New speed =3x/4 kmph Total distance = y km ∴ y/(3x/4) - y/x = 20/60 = (3/4 - 1) y/x = 1/3 = y/x = 1 ∴ Required time = 60 minutes
By: Pranav Gupta ProfileResourcesReport error
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