send mail to support@abhimanu.com mentioning your email id and mobileno registered with us! if details not recieved
Resend Opt after 60 Sec.
By Loging in you agree to Terms of Services and Privacy Policy
Claim your free MCQ
Please specify
Sorry for the inconvenience but we’re performing some maintenance at the moment. Website can be slow during this phase..
Please verify your mobile number
Login not allowed, Please logout from existing browser
Please update your name
Subscribe to Notifications
Stay updated with the latest Current affairs and other important updates regarding video Lectures, Test Schedules, live sessions etc..
Your Free user account at abhipedia has been created.
Remember, success is a journey, not a destination. Stay motivated and keep moving forward!
Refer & Earn
Enquire Now
My Abhipedia Earning
Kindly Login to view your earning
Support
Type your modal answer and submitt for approval
Prem and Shyam decide to go on a trip to point Y on a particular day from point X. Prem leaves for point Y at 11 : 00 am, at speed of 72 km/hour. Shyam leaves for point Y at 11: 30 same day as Prem left. At what speed should Shyam travel to catch up with Prem in 4 hours ? (in km/hour)
85
81
80
82
Distance covered by Prem in half an hour = 72 × 1/2 = 36 km Shyam has to cover an additional distance of 36 km in 4 hours. Relative speed of Shyam =(x - 72)kmph ∴ 36/(x- 72) = 4 = x - 72 = 9 = x = 81 kmph
By: Pranav Gupta ProfileResourcesReport error
Access to prime resources
New Courses