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wo equal circles of radius 4 cm intersect each other such that each passes through the centre of the other. The length of the common chord is :
2√3cm
4√3cm
2√2cm
8cm
Radius, OA = 4cm ∴ OC = 2cm By Pythagoras theorem in ΔAOC, ∴ AC = √(42 – 22)=√12 = 2√3cm ∴ AB = 2√3+ 2√3= 4√3cm
By: MIRZA SADDAM HUSSAIN ProfileResourcesReport error
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