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A, B and C are the three points on a circle such that the angles subtended by the chords AB and AC at the centre O are 90° and 110° respectively. ∠BAC is equal to
170°
70°
90°
80°
We know that, ∠BOA + ∠AOC + ∠BOC = 360° 90° + 110° + ∠BOC = 360° ∠BOC = 360° – 200° = 160° Note : The angle subtended by an arc of a circle at the centre is double the angle subtended by it at any point on the remaining part of the circle. ∴ ∠BAC = 1/2∠BOC = 1/2× 160° = 80°
By: MIRZA SADDAM HUSSAIN ProfileResourcesReport error
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