The length of a class room floor exceeds its breadth by 25 m The area of the floor remains unchanged...........

Quantitative Aptitude ( CCS) Mensuration 2D

The length of a class room floor exceeds its breadth by 25 m. The area of the floor remains unchanged when the length is decreased by 10 m but the breadth is increased by 8 m. The area of the floor is

5100 sq.m

4870 sq.m

4987 sq.m

4442 sq.m

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Explanation:

Let the breadth of floor be 'b' m.
Then, length of the floor is 'l = (b + 25)'
Area of the rectangular floor = l x b = (b + 25) × b
According to the question,
(b + 15) (b + 8) = (b + 25) × b
b^2 + 8b + 15b + 120 = b^2 + 25b
2b = 120
b = 60 m.
l = b + 25 = 60 + 25 = 85 m.
Area of the floor = 85 × 60 = 5100 sq.m.