A man travelled a distance of 75 km in 5 hours partly on foot at the rate of 6 km hour and partly by...........

Quantitative Aptitude ( CCS) Mixture and Alligation

A man travelled a distance of 75 km in 5 hours partly on foot at the rate of 6 km/hour and partly by scooter at 18 km/hour. Find the distance travelled by scooter?

56 km

52.25 km

48.5 km

67.5 km

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Explanation:

Average speed = 75/5 = 15 km/hr
By method of allegation:
6 18
. 15
3 9
1 : 3
1 : 3 is the ratio of times.
So time by scooter = 3/(1+3) * 5 = 3.75 hrs
So distance by scooter = 3.75 * 18 = 67.5

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2nd method

Let distnace covered by scooter=x
then distnace covered by foot=75-x

x/18 + (75-x)/6=5
x+225-3x=5 *18
-2x=-135
x=67.5