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A mixture contains milk and water in the ratio 2 : 3 and the other contains them in the ratio 3 : 1 respectively. What weight of 2nd mixture must be taken so as to make a third mixture 7 litres in weight with 70% milk?
1 litre
4 litres
6 litres
10 litres
70/100 = 7/10 Milk in first = 2/(2+3) = 2/5, milk in second = 3/(3+1) = 3/4 By method of allegation: 2/5 3/4 7/10 3/4 – 7/10 7/10 – 2/5 1/20 : 3/10 1 : 6 So in 3rd mixture, 2nd mixture is [6/(1+6)] * 7 = 6 litre
By: Manpreet kaur ProfileResourcesReport error
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