A bus started its journey from Ramgarh and reached Devgarh in 44 minutes with its average speed of 5...........

Quantitative Aptitude ( CCS) Time & distance

A bus started its journey from Ramgarh and reached Devgarh in 44 minutes with its average speed of 50 km/hour. If the average speed of the bus is increased by 5 km/hour, how much time will it take to cover , the same distance ?

40 minutes

38 minutes

36 minutes

31 minutes

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Explanation:

Distance between Ramgarh and Devgarh = (50 × 44/60) = 110/3
New speed = 55 kmph
= 55/60 km/minute
∴ Required Time = Distance/ Speed
= 110/3 × 60/55 = 40 minutes