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The perimeters of two squares are 40cm and 32 cm. Find the perimeter of a third square whose area is equal to the difference of the areas of the two squares.
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23
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25
side of first square = 40/4 =10cm side of second square = 32/4 = 8cm area of third squre = 10² - 8² = 36 sq cm side of third square = √36 = 6 cm required perimeter = 6*4 = 24cm
By: MIRZA SADDAM HUSSAIN ProfileResourcesReport error
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