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The difference between two parallel sides of a trapezium is 4 cm. perpendicular distance between them is 19 cm. If the area of the trapezium is 475 find the lengths of the parallel sides.
27 and 23
24 and 23
25 and 23
22 and 23
Let the two parallel sides of the trapezium be a cm and b cm. Then, a - b = 4 And, (1/2)×(a+b)×19=475 =>(a+b)=50 Solving (i) and (ii), we get: a = 27, b = 23. So, the two parallel sides are 27 cm and 23 cm.
By: MIRZA SADDAM HUSSAIN ProfileResourcesReport error
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