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At a casino in mumbai, there are three tables A, B and C. The payoffs at A is 10:1, at B is 20:1 and at C is 30:1. If a man bets Rs 200 at each table and win at two of the tables, what is the maximum and minimum difference between his earnings can be?
2000
2500
3000
4000
Maximum earning will be only when he will won on the maximum yielding table.
A ----> 10:1
B ----> 20:1
C ----> 30:1
i.e, he won on B and C but lost on A
20 x 200 + 30 x 200 -1 x 200 = 9800
minimum earning will be when he won on table A and B and lose on that table 3.
Therefore, 10 x 200 + 20 x 200 - 1 x 200 = 6000-200 = 5800
Therefore, Difference= 9800 - 5800 = 4000
Hence, option 4 is the correct answer.
By: Amit Kumar ProfileResourcesReport error
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