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Three circles of radius 3.5cm are placed in such a way that each circle touches the other two. The area of the portion enclosed by the circles is
1.967
1.658
1.35
none of these
required area = (area of an equilateral triangle of side 7 cm)- (3 * area of sector with à = 60 degrees and r = 3.5cm) ((√3/4)*7*7)−(3*(22/7)*3.5*3.5*60/360) sq cm =(√3/4*49)−(11*0.5*3.5)sq cm = 1.967 sq cm
By: MIRZA SADDAM HUSSAIN ProfileResourcesReport error
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