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A rectangular park 60 m long and 40 m wide has two concrete crossroads running in the middle of the park and rest of the park has been used as a lawn. If the area of the lawn is 2109 sq. m, then what is the width of the road?
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Area of the park = (60 x 40) = 2400m^2 Area of the lawn = 2109m^2 Area of the crossroads = (2400 - 2109) = 291m^2 Let the width of the road be x metres. Then, 60x+40x−X^2=291 x^2−100x+291=0 (x - 97)(x - 3) = 0 x = 3.
By: MIRZA SADDAM HUSSAIN ProfileResourcesReport error
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