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A parallelogram has sides 30m and 14m and one of its diagonals is 40m long. Then its area is
236
368
398
336
let ABCD be the given parallelogram area of parallelogram ABCD = 2 x (area of triangle ABC) now a = 30m, b = 14m and c = 40m s=1/2 x (30+14+40) = 42 Area of triangle ABC = √[s(s−a)(s−b)(s−c)] = √[42(12)(28)(2)]= 168sq m area of parallelogram ABCD = 2 x 168 = 336 sq m
By: MIRZA SADDAM HUSSAIN ProfileResourcesReport error
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