A man drives 150 km from A to B in 3 hours 20 minutes and returns to A in 4 hours 10 minutes Then av...........

Quantitative Aptitude ( CCS) Time & distance

A man drives 150 km from A to B in 3 hours 20 minutes and returns to A in 4 hours 10 minutes. Then, average speed from A to B exceeds the average speed for the entire trip by

5 km/hr

4.5 km/hr

4 km/hr

2.5 km/hr

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Explanation:

average speed =total distance/ total time taken
distance=150+150=300 km total time 7hours and 30 minutes =15/2
average speed of entire trip(A1)=300 divided by 15/2 =600/15= 40 km/hrs
time 3 hours 20 minutes=3 and 1/3 hours=10/3 hours
average speed of trip from A to =150 divided by 10/3=450/10= 45 km/hrs
exceed by A1=45-40= 5 km/hrs
Hence, option 1 is the correct answer.