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The value of (sinθ−2sin3θ)/(2cos3θ−cosθ) is,
sinθ
cotθ
cosθ
tanθ
sinθ and cosθ appear both in numerator and denominator in similar forms and ready to be factored out, (sinθ−2sin3θ)/(2cos3θ−cosθ)=tanθ(1−2sin2θ)/(2cos2θ−1) tanθ(cos2θ−sin2θ)/(cos2θ−sin2θ) =tanθ
By: MIRZA SADDAM HUSSAIN ProfileResourcesReport error
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