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A regular hexagonal prism has its perimeter of base as 600 cm and height 200 cm. Find weight of petrol that it can hold if density is 0.8 g/cc. (Take √3 = 1.73)
4100 kg
5241 kg
4152 kg
none of these
Side of hexagon = (Perimeter) / (Number of Sides) = 600/6 = 100 cm. Area of regular hexagon = (3√3) / 2 x 100 x 100 = 25,950 sq.cm. Volume = Base Area × height = 25950 x 200 = 5,190,000 cu.cm Weight of petrol = Volume x Density = 5,190,000 cc × 0.8 g/cc = 4,152,000 gm. = 4,152 kg.
By: MIRZA SADDAM HUSSAIN ProfileResourcesReport error
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