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The perimeter of a rectangle whose length is 6 m more than its breadth is 84 m. What will be the area of the rectangle?
333 sq.mts
330 sq.mts
362 sq.mts
432 sq.mts
Let the breadth of the rectangle = b mts Then Length of the rectangle = b + 6 mts Given perimeter = 84 mts 2(L + B) = 84 mts 2(b+6 + b) = 84 2(2b + 6) = 84 4b + 12 = 84 4b = 84 - 12 4b = 72 b = 18 mts => Length = b + 6 = 18 + 6 = 24 mts Now, required Area of the rectangle = L x B = 24 x 18 = 432 sq. mts
By: MIRZA SADDAM HUSSAIN ProfileResourcesReport error
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