Problems based on Ages

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Present age of a father is three times more than his son. 8 years hence, father’s age will be 2 and a half times of his son’s age. After 8 more years, how many times would father be his son’s age?

3.5 times

4 times

1.5 times

2 times

Explanation:

three times more than
Let present age of son = x, then of father = x+3x = 4x
After 8 years, (4x+8) = (5/2) (x+8)
Solve, x = 8
Required ratio = (4x+16) : (x+16) = 2 : 1

By: Manpreet kaur

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