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After 10 years, A’s age will be twice that of B’s age. A’s present age is 6 times that of C. If B’s eighth birthday was celebrated 2 years ago, then what is C’s present age?
Let C’s present age = x, then A’s present age = 6x
Let B’s present age is y.
Then after 10 years, (6x+10) = 2 (y+10)
Solve, y = 3x-5 = B’s present age
B’s eighth birthday was celebrated 2 years ago, so B’s present age = 10, and also 3x-5 = 10
Solve, x = 5
By: Manpreet kaur ProfileResourcesReport error
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