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One year ago the ratio between Sam and Ash’s age was 4:3. One year hence the ratio of their ages will be 5:4. What is the sum of their present ages in years?
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Let one year ago Sam’s age be 4X years And, Ash’s age be 3X years Present age of Sam = (4X + 1) years Present age of Ash= (3X + 1) years One year hence Sam’s age = (4X + 2) years Ash’s age = (3X + 2) years According to question, [4X + 2] divide by [3X + 2] = 5 / 4 16X + 8 = 15X + 10 or, X = 2 Sum of their present ages = 4X + 1 + 3X + 1 = 7X + 2 = 7 x 2 + 2 = 16 years.
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